复制
收藏
提问
简洁
a(i)=(100.*(((x(i+1)-x(i).^2)).^2)+(x(i)-1).^2);
4月前
全网
文档
学术
百科
知识库
回答简洁模式
深入研究一些
It seems like you've provided a MATLAB code snippet and are likely looking for an explanation or a specific question related to it. The code snippet defines a vector a
based on the elements of another vector x
. Here's a breakdown of the code:
a(i) = (100 * (((x(i+1) - x(i)^2)^2) + (x(i) - 1)^2));
x(i)
: This represents thei
-th element of the vectorx
.x(i+1)
: This represents the(i+1)
-th element of the vectorx
.x(i)^2
: This squares thei
-th element ofx
.x(i+1) - x(i)^2
: This calculates the difference between the(i+1)
-th element and the square of thei
-th element.100 * (((x(i+1) - x(i)^2)^2)
: This scales the squared difference by a factor of 100.(x(i) - 1)^2
: This squares the difference between thei
-th element ofx
and 1.(100 * (((x(i+1) - x(i)^2)^2) + (x(i) - 1)^2)
: This adds the scaled squared difference to the squared difference of thei
-th element and 1.
The code is likely part of a larger script that is computing a sequence of values for a
based on corresponding values in x
. It's important to note that this code assumes that x
is a vector with at least i+1
elements to avoid indexing errors.
If you have a specific question about this code or its context, please provide more details, and I'll be happy to assist you further.
你觉得结果怎么样?